Geopuzzle (29)
Given
Solution:
Calculation:
L
MBA=(180-48)/2=66
L
CAB=66-36=30
boogBC=60
L
BMC=60
MB=MC=BC
L
AEM=(180-36)/2=72
L
BME=72-48=24
L
MCA=36
BC=BM en EM=EC : BF is perpendicular bisector of MC
BCDM is a rhombus.
x=
L
MBF=
L
DBC=30