Geopuzzle (29)


Given



Solution:



Calculation:
LMBA=(180-48)/2=66
LCAB=66-36=30
boogBC=60
LBMC=60
MB=MC=BC
LAEM=(180-36)/2=72
LBME=72-48=24
LMCA=36
BC=BM en EM=EC : BF is perpendicular bisector of MC
BCDM is a rhombus.
x=LMBF=LDBC=30